Revolving door for a building
Outlier Articles Home

Calculus

Disk Method: Definition, Formula & Examples

06.03.2022 • 8 min read

Rachel McLean

Subject Matter Expert

In this article, we’ll discuss how to use the disk method. Then, we’ll practice with some examples. We’ll also compare the disk and washer methods and learn how to determine when to use each method.

In This Article

  1. What Is the Disk Method?

  2. What Is the Disc Method Formula?

  3. 3 Steps on How To Use the Disk Method

  4. Disk vs Washer Method

  5. Washer Method Example

What Is the Disk Method?

When a two-dimensional area is rotated around a line, it creates a three-dimensional solid of revolution. For example, when a rectangle is rotated about the x-axis, it generates a disk.

In the image below, WW is the width of the rectangle, and RR is the height of the rectangle. RR becomes the radius of the disk when the rectangle is revolved around the x-axis.

In the graphic, W is the width of the rectangle and R is the height of the rectangle. R becomes the radius of the disk when the rectangle is revolved around the x-axis

You can think about a revolving door to help visualize this process. As a revolving door moves, the outer edge of the door follows a circular path about the axis of rotation. Once the door revolves completely about its axis, the space through which it passed is in the shape of a cylinder.

The line that a curve rotates around is called the axis of rotation. In the image above, the x-axis is our axis of rotation. The shape of the resulting solid is a disk, which is a cylinder. So, we can use the formula for the volume of a cylinder to find its volume.

Volume=π(R2)(W)\text{Volume} = \pi(R^2)(W)

So, to find the volume of a solid of revolution, we can cut the curve into a series of thin rectangles, which cuts the solid of revolution into a series of thin disk-shaped slices. Adding up the volume of each slice gives us an approximation of the solid’s volume.

A disk method graphic showing rotation around a horizontal axis and  rotation around a vertical axis

Cutting the solid into a finite number of slices gives us an approximation of the volume. To calculate the precise volume, we need to use infinite slices. This process will require integration.

To find the volume of each infinitely small slice, we’ll reuse the formula for the volume of a cylinder. Each slice of the solid is also called a cross-section, and must be perpendicular to the axis of rotation. This time, the width is Δx\Delta x and the radius is the height of the function at xx.

This method of slicing to determine the volume of a solid of revolution is called the disk method.

What Is the Disc Method Formula?

There are two variations of the disk method formula. We use the first variation for a horizontal axis of rotation. We use the second variation for a vertical axis of rotation.

Disc Method Formula with Horizontal Axis

Here’s the formula for using the disk method with a horizontal axis of rotation. In this case, we integrate with respect to xx. If ff is non-negative and continuous on the interval [a,b][a, b], then the volume formed by rotating the area under the curve of ff about a horizontal axis is the definite integral given by:

V=abπR2dx\text{V} =\int_a^b \pi R^2\,dx

RR is the distance between the top function and the axis of rotation. It is given by RR = (top function) - (bottom function). If the axis of rotation is the x-axis, RR is simply [f(x)][f(x)]. The bounded region should be flush to the axis of rotation so that the solid of revolution has no holes.

Disc Method Formula With Vertical Axis

Here’s the formula for using the disk method with a vertical axis of rotation. In this case, we integrate with respect to yy. If gg is non-negative and continuous on the interval [a,b][a, b], then the volume formed by rotating the area under the curve of gg about a vertical axis is the definite integral given by:

V=abπR2dy\text{V} =\int_a^b \pi R^2\,dy

Again, RR is the distance between the top function and the axis of rotation, and is given by RR = (top function) - (bottom function). If the axis of rotation is the y-axis, RR is simply [g(y)][g(y)].

You can think about an orange to help visualize this integration process. If you cut an orange into thin circular slices, the orange is transformed into the sum of many “disks”. Finding the volume of each disk and adding them together gives you the volume of the entire orange.

3 Steps on How To Use the Disk Method

Here are 3 steps to using the disk method:

  1. Graph the bounded region.

  2. Identify the axis of rotation, and then draw a slice perpendicular to the axis of rotation.

  3. Substitute your function and its bounds into the disk method formula and integrate.

Let’s do a few disk method examples together.

Example 1

Let f(x)=x2f(x) = x^2. Consider the region bounded by f(x)f(x), x=0x = 0, x=1x = 1, and the x-axis. Find the volume of the solid generated by revolving the described region around the x-axis.

Step 1 and 2

Our bounded region looks like this. The black vertical line represents one slice of the curve.

Graph of bounded region with black vertical line representing one slice of the curve

Step 3

Since we are rotating around the x-axis, R=[f(x)]R = [f(x)]. Now we can plug our function into the disk method equation. We’ll use the power rule to integrate.

V=abπR2dx\text{V} =\int_a^b \pi R^2\,dx
V=01π[f(x)]2dx\text{V} =\int_0^1 \pi [f(x)]^2 \,dx
V=π01(x2)2dx \text{V} =\pi \int_0^1 (x^2)^2 \,dx
V=π01x4dx\text{V} =\pi \int_0^1 x^4 \,dx
V=πx5501\text{V} = \pi \frac{x^5}{5} \Big|_0^1
V=π5\text{V} = \frac{\pi}{5}

The volume of the solid of revolution is π5\frac{\pi}{5}. The generated solid looks like a curved funnel.

Disk method graph showing the volume of the solid of revolution with the generated solid looking like a curved funnel.

Dr. Tim Chartier—an award-winning professor of mathematics and computer science at Davidson College—explains more about the power rule:

Example 2

Let f(x)=x2f(x) = x^2. Consider the region bounded by f(x)f(x), x=0x = 0, x=1x = 1, and the y-axis. Find the volume of the solid generated by revolving the described region around the y-axis. Note that our axis of revolution has changed to the y-axis.

Step 1 and 2

Since our axis of rotation is the y-axis, we need to rewrite our equation to solve for xx as a function of yy, instead of yy as a function of xx. Taking the square root of each side, this gives us x=yx = \sqrt{y}.

Now our bounded region looks like this, where the white horizontal line represents one slice of the curve.

Graph with bounded region where the white horizontal line represents one slice of the curve

Step 3

Since we are rotating around the y-axis, R=[f(y)]R = [f(y)]. Now, we can plug our function into the disk method equation. Again, we’ll use the power rule to integrate.

V=abπR2dy\text{V} =\int_a^b \pi R^2\,dy
V=01π[f(y)]2dy\text{V} =\int_0^1 \pi [f(y)]^2 \,dy
V=π01(y)2dy\text{V} =\pi \int_0^1 (\sqrt{y})^2 \,dy
V=π01ydy\text{V} =\pi \int_0^1 y \,dy
V=πy2201\text{V} = \pi \frac{y^2}{2} \Big|_0^1
V=π2\text{V} = \frac{\pi}{2}

The volume of the solid of revolution is π2\frac{\pi}{2}. Note that both the volume and shape of the generated solid are different than the volume and shape of the same function revolved around the x-axis.

Disk Method graph with axis of revolution

Disk vs Washer Method

When we can’t use the disk method, the washer method is another way to calculate the volume of a solid of revolution.

Like the disk method, the washer method requires that the slice is perpendicular to the axis of revolution. However, in this method, the bounded region is not flush to the axis of revolution. Therefore, the solid generated by each slice looks like a washer—a disk with a hole in it. The corresponding solid of revolution also has a hole.

Graph with a corresponding solid of revolution that has a hole.

Here’s the formula for using the washer method with a horizontal axis of rotation. In this case, we integrate with respect to xx. If ff and gg are non-negative and continuous on the interval [a,b][a, b], and fgf\geq g for all xx in [a,b][a,b], then the volume formed by rotating the area bounded by ff, gg, x=ax = a and x=bx = b about a horizontal axis is given by:

V=abπ(R2r2)dx\text{V} =\int_a^b \pi (R^2 - r^2)\,dx

3 Steps To Use Washer Method

Here are 3 steps to using the washer method:

  1. Graph the bounded region.

  2. Identify the axis of rotation by drawing a slice perpendicular to the axis of rotation.

  3. Calculate RR and rr. Substitute these values and the bounds into the washer method formula and integrate.

Washer Method Example

Let’s look at an example to showcase the difference between the disk vs washer method. Consider the region bounded by y=x2y = x^2 and y=xy = x on the interval [0,1][0, 1]. Find the volume of the region when it is rotated about the line y=2y = 2.

Step 1 and 2

Our bounded region looks like this. The small white vertical black line represents one slice of the curve.

Graph of bounded region with a small vertical white line representing one slice of the curve.

Step 3

RR is the distance from the axis of rotation to the outer curve. In this case, our axis of rotation is y=2y = 2 and the outer curve is y=x2y = x^2. So, R=2x2R = 2 - x^2.

The lowercase rr is the distance from the axis of rotation to the inner curve. Our axis of rotation is y=2y = 2 and the inner curve is y=xy = x. So, r=2xr = 2 - x. Now, we can plug these values into the washer method formula and solve.

V=abπ(R2r2)dx\text{V} = \int_a^b \pi (R^2 - r^2)\,dx
V=01π([2x2]2[2x]2)dx\text{V} = \int_0^1 \pi ([2-x^2]^2 - [2-x]^2)\,dx
V=π01(x45x2+4x)dx\text{V} = \pi \int_0^1 (x^4 - 5x^2 + 4x)\,dx
V=π(x555x33+4x22)01\text{V} = \pi(\frac{x^5}{5} - \frac{5x^3}{3}+\frac{4x^2}{2}) \Big|_0^1
V=8π15\text{V} =\frac{8\pi}{15}

Using the washer method, we’ve found that the volume of the solid of revolution is 8π15\frac{8\pi}{15}.

Explore Outlier's Award-Winning For-Credit Courses

Outlier (from the co-founder of MasterClass) has brought together some of the world's best instructors, game designers, and filmmakers to create the future of online college.

Check out these related courses:

Calculus I

Calculus I

The mathematics of change.

Explore course
Intro to Statistics

Intro to Statistics

How data describes our world.

Explore course
Intro to Microeconomics

Intro to Microeconomics

Why small choices have big impact.

Explore course

Share